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Electrostatics

Capacitance (Dielectric)

Explain the effect of inserting a dielectric slab of constant κ fully between the plates of a parallel plate capacitor. Derive the expression for the new capacitance.

LA
Hard
5 Marks
80% Confidence

Confidence Score

80%

Times Viewed

0

Max Marks

5

Hints

  • 1.bound charge reduces field
  • 2.effective permittivity = κε₀
  • 3.C = κε₀A/d

Answer Outline

  1. 1.Original C = ε₀A/d
  2. 2.With dielectric, field reduces by factor 1/κ
  3. 3.So C increases: C' = κC = κε₀A/d
  4. 4.Explain polarization and reduced effective field

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